Here is a simple Java program that counts the number of digits in a given integer:
Problem
Here is example of the problem –
Enter an Number : 12345 Number of digits in 12345 : 5
Algorithm:
- Start program,
- Read or input a number,
- declare an integer variable count initialize it with 0,
- Divide the number with 10 till the number is 0, and for each turn increase the count.
Code:
import java.util.Scanner;
public class NumberOfDigits {
public static void main(String[] args) {
int Number;
int count=0;
Scanner sc = new Scanner(System.in);
System.out.println("Enter any Number: ");
Number = sc.nextInt();
while(Number > 0) {
Number = Number / 10;
count++;
}
System.out.println("Number of digits in a given number is "+count);
}
}
import java.util.Scanner;
public class NumberOfDigits {
public static void main(String[] args) {
int Number;
int count=0;
Scanner sc = new Scanner(System.in);
System.out.println("Enter any Number: ");
Number = sc.nextInt();
while(Number > 0) {
Number = Number / 10;
count++;
}
System.out.println("Number of digits in a given number is "+count);
}
}
import java.util.Scanner;
public class NumberOfDigits {
public static void main(String[] args) {
int Number;
int count=0;
Scanner sc = new Scanner(System.in);
System.out.println("Enter any Number: ");
Number = sc.nextInt();
while(Number > 0) {
Number = Number / 10;
count++;
}
System.out.println("Number of digits in a given number is "+count);
}
}
Output:
Enter any Number:
1234
Number of digits in a given number is 4
Enter any Number:
1234
Number of digits in a given number is 4
Enter any Number: 1234 Number of digits in a given number is 4